16x^2+18+1=16

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Solution for 16x^2+18+1=16 equation: 



16x^2+18+1=16

We move all terms to the left:

16x^2+18+1-(16)=0

We add all the numbers together, and all the variables

16x^2+3=0

a = 16; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·16·3
Δ = -192
Delta is less than zero, so there is no solution for the equation

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